These are the formulae that will be supplied for the exam
t = | b | t = | (01– 02) |
Sb (S0-0 )
t = r√(n–2 t = | đ |
√(1–r²) SEđ
S²(variance) = ∑x²- (∑x)²/n
(n-1)
S0 = SE0 = S/√n = √(s²/n) S0 -0 = √(S1²/n1 + S2²/n2) SEđ = √ Sđ²/n
F= MSbetw/MSwithin MS=SS/df Y’ = a + b(x) 𝒳² = ∑ (O-E)²/E
Expected# = (row.tot) x (col.tot) ÷ (grand tot) P(FET) = (a+c)! x (b+d)! x (a+b)! x (c+d)!
a! x b! x c! x d! x (a+b+c+d)!
CL95% = 0 ± t(0.05)(n-1df)(S0) CL95% = b ± t(0.05)(n-2df)(Sb)