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Back to ENH440 Problems & Solutions
Solution in detail.......#52 |
Note that
you do not have the complete data, only the means, totals, and N for each
group.
Null hypothesis: That there is
NO real difference in
effectiveness between the means of three
pesticide types
and that any observed difference is only due to random (chance) error.
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ANOVA |
ss |
df |
ms |
F |
P |
bss |
486.01 |
2 |
243.00 |
6.17 |
<0.01 |
wss |
1655.24 |
42 |
39.41 |
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tss |
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44 |
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calculated
F:
6.17 exceeds critical
F(0.01)(2,42 df)
= (less than 5.18)
therefore can reject Ho
P<0.01
There was a difference between the means that
is unlikely (less than 1% likely) to have been due to chance alone. We can reject the null
hypothesis and claim statistical significance at 0.01 level The
highest (best) efficiency in
terms of insect kill rate out of 50 was from method B (38/50), followed by method
A (20/50), while the
lowest score was associated with method C (12/50)
Method B is approximately twice as efficient as A and more than 3 times as
efficient as C.
Please note (Nov 9, 2012): the values shown in
red
have been adjusted to correct some editing errors.
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