PROTEUS

              

 

 

 

 

 

 

 

 

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Solution in detail.......#24

Null hypothesis: "no difference in days needed for recovery between the two treatment methods"

 

Two groups:  heat N=6,   mean = 10.333,    SD=  3.445

                                          elec N=7,   mean= 11.714      SD=  3.684 

 

        calculated  t   =  1.381/1.979 =  0.698            Compare with t(0.05)(11df) =   2.20      

 

Thus calc t does not meet critical t.  Null H cannot be rejected.  There was a slight difference (heat was marginally better) in days to recovery between the two methods but this difference was not statistically significant.  The probability of seeing a difference of this magnitude on the basis of chance alone is more than 5%       

       

             mean (heat): 10.33 days; mean (elec): 11.71 days     t: 0.698,  11 df,  P > 0.05