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Solution in detail:#17

#1#17  

    Null hypothesis:  Ho: "There is no real difference between York

     and Ryerson in terms of the test scores. Any observed difference

     is therefore due to chance (random error)".  [Ho: xR = xY]

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   Data:   York: 12, 15, 19, 11, 18, 14, 13, 10, 16, 17, 15, 14.  

             n=12,   = 14.500    s= 2.746899   Σx=  174    Σx2=  2606

 

             Ryerson: 15, 11, 17, 18, 19, 17, 19, 19, 12, 13, 16. 

              n=11,    = 16.000    s= 2.898275    Σx 176     Σx2 2900

 

   Analysis:

                                     | xR - xY |                1.500 

                          t  =    ----------------      =    -----------      =       1.2712       

                        ﴾SxR-xY﴿              1.1800

      

        calculated  t   =  1.271

        critical  t(0.05, 21df)   =    2.08      

         t(calc) does not meet or exceed the t(crit),   Cannot reject  Ho.

 

   Summary:  There was a slight difference observed between Ryerson and York in terms of the student scores. (Ryerson mean: 16.00, York mean:14.5). The difference was not statistically significant and could easily have occurred by chance alone more than 5% of the time.  We cannot reject the null hypothesis as stated above, and conclude that on the basis of the data provided, no real difference exists between the two universities in this test.  

 

         (xR - xY): 1.5,      21 df       t: 1.271 ,      P > 0.05   n.s.